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Multiple Choice Questions

If a b c 0 and x y z Then x a 2 y b z c y b 2 x a z c z c 2 x a y b is equal to ........

Quantitative Aptitude (CCS) Algebra

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If a+b+c= 0 and x=y+z Then [(x-a)²/(y+b) (z+c)] + [ (y+b)²/(x-a) (z+c)] + [(z+c)²/(x-a) (y+b)] is equal to

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Explanation:

a+b+c=0 and x-y-z=0
so (x-a)- (y+b) –(z+c) = 0
Now ,
[(x-a)²/(y+b) (z+c)] + [ (y+b)²/(x-a) (z+c)] + [(z+c)²/(x-a) (y+b)]
We know that p3 + q³ + r³=3pqr ( where p+q+r=0)
so (p³+ q³ + r³)/pqr =3
[(x-a)²/(y+b) (z+c)] + [ (y+b)²/(x-a) (z+c)] + [(z+c)²/(x-a) (y+b)]
=3