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Directions: Following Line Graph represents the uniform speed of Trains (A, B, C, D and E) on two different days in meter per second and the Bar Chart represents the length of each train in meter.
Approximately what is the average time taken by train D on day 1 and day 2 to cross the platform of length 500 meter?
6 Sec
9 Sec
12 Sec
Data Insufficient
Time= Distance/Speed Time taken on day 1, t1= (train length + Platform Length)/speed = (225+500)/200 = 3.6 sec Time taken on day 2, t2= (train length + Platform Length)/speed = (225+500)/50 = 14.5 sec Average time = (t1+t2)/2 = 9 seconds
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