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A district has 64000 inhabitants. If the population increases at the rate of 2 * 1/2 % per annum, then the number of inhabitants at the end of 3 years will be :
65380
68921
70987
72345
Population afer 3 years = 64000 * (1 + 5/(2 *100) )3
= (64000 * 41/40 * 41/40 * 41/40 ) = 68921.
Hence, option 2 is the correct answer.
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