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Direction: Study the following Table and answer the questions that follow:
Due to fever Tipu did not joined the work but Ismail took his place , who can complete the work in 25 days. He did Tipu’s part of work. After that khachara joined the work but worked for same number of days as Ismail. If remaining work was completed by Bagha who is 300% more efficient than Lakha then in how many days was the whole work completed?
60
15
16
63/2
25/13
Explanation – Ismail completes work in = 25 days Kachara completes work in = 20 days Bagha is 300% more efficient than Lakha, so we can find that in how many days Bagha can complete this work. (100 + 300)% of Bagha = Lakha from the table we can calculate that Lakha can complete the whole work in 32 days 400% of Bagha = 32 ( number of days in which Lakha can complete the work) Bagha = (32/400) × 100 = 8 days Total work = LCM ( Ismail, Kachara and Bagha) = LCM ( 25, 20 , 8) = 200 unit Now we can find efficiency of each persons. Ismail = 8 unit Kachara = 10 unit Bagha = 25 unit Ismail did only 25% of total work i.e. 50 unit No. of days Ismail took to complete 25% work = 50 / 8 = 25/4 days No. of days Kachara works = 25/4 days ( said in question) Work done by Kachara = 10 × (25/4) = 125/2 unit Remaining work = 200 – ( 50 + 125/2) = 175 / 2 unit Remaining work done by Bagha = (175/2) / 25 = 175/50 = 7/2 days Total work completes in = (25/4) + (25/4) + (7/2) = 32/2 = 16 days
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