A gives B a head start of 10 seconds in a 1500 m race and both finish the race at the same time What...........

Quantitative Aptitude (CPO) Time & distance

A gives B a head-start of 10 seconds in a 1500 m race and both finish the race at the same time. What is the time taken by A (in

minutes) to finish the race if speed of B is 6 m/s?

This questions was previously asked in

SSC CPO 11th Nov 2022 Shift 2

Let's break down the problem and determine the time taken by A.

- B's speed is given as 6 m/s.

- B gets a head-start of 10 seconds.

- In 10 seconds, B covers \(6 \, m/s \times 10 \, s = 60 \, m\).

- So, B covers the remaining \(1500 \, m - 60 \, m = 1440 \, m\) after the head-start.

- Time taken by B to cover 1440 m is \(1440 \, m / 6 \, m/s = 240 \, s\).

- Since A finishes at the same time as B, A also takes 240 seconds to cover the whole 1500 m.

- Converting seconds to minutes: \(\frac{240 \, s}{60 \, s/min} = 4 \, min\).

So, A takes 4 minutes to finish the race.

- Option 1, 3: Incorrect, as they don't match the calculated time.

- Option 2, 4: Correct; A takes 4 minutes.

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