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The sum and difference of the LCM and the H.C.F. of two numbers are 312 and 264 respectively. Find the numbers if their sum is 168.
96, 78
72, 96
108, 84
None of these
Let the L.C.M Be 'L' and H.C.F be 'H'.
L + H = 312 ------------> (i)
L - H = 264 ------------>(ii)
By (i) and (ii) :-
L = 288
H = 24
Sum of the numbers is 168.
The Numbers must be 24x and 24y since the H.C.F is 24.
So 24x + 24y = 168
(x + y) = 7
Possible Values of x and y for which the L.C.M of these numbers will be 288 :-
(3,4) or it can be taken as (4,3).
Hence the numbers are 24*3 = 72 and 24*4 = 96.
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