f all the boxes are arranged in alphabetical order from bottom to top how many boxes will remain in ...........

Logical Reasoning(SBI-CL) Puzzle Test

Direction: Read the information given below and answer the question that follows

There are seven boxes – Z, A, V, B, U, C and W which are placed one above the other but not necessarily in the same order. The bottom box is numbered 1 and the box above it numbered 2 and so on till the top box which is numbered 7. Two boxes are placed between V and Z, which is kept at an odd number position above V. Two boxes are kept between A and W. Three boxes are kept between Z and W. B is kept immediately above U, which is not kept above V.

f all the boxes are arranged in alphabetical order from bottom to top, how many boxes will remain in the same position?

This questions was previously asked in

SBI Clerk Pre 2022 (Shift 2)

View All SBICler Previous Year Papers

One

Three

Two

More than three

None

Explanation:

- Start by placing Z at an odd position above V. The possible positions for Z could be 3, 5, or 7.

- Place two boxes between Z and W. This means if Z is at position 5, W should be at position 1 or 9, but since there are only 7 positions, logically Z at position 3 or 5 works, putting W at position 7 or 1 respectively.

- Place B immediately above U, which cannot be above V. Hence, U must be below V and B right above U.

- Two boxes between A and W. If W is at position 1 and there are three boxes between Z and W, Z should be at position 5, causing A to be at position 4 or 6.

- Arrange boxes alphabetically and see which stays in place.

Upon analyzing the setup:

- If W is at the bottom, positions can be as follows: W, U, B, V, A, C, Z.

- In alphabetical order: A, B, C, U, V, W, Z.

- In this sequence, B and V remain in the same place.

The answer is: Option 3 - Two