If B works with 60 more than his minimum efficiency then find the total time of rest of B in his ent...........

Quantitative Aptitude (SBI-PO) Time and work

Directions: Refer the table given below and answer the the following questions with the help of Actual work done by persons A, B and C with the maximum time required by each to complete the work. Data about three persons A, B and C is given in the table below:

Person Actual work done Maximum time(in hours)

A 50 units 10

B 60 units 12

C 15

If B works with 60% more than his minimum efficiency. then, find the total time of rest of B in his entire duration of work.

This questions was previously asked in

SBI PO Prelims (02 Jan, 2022)

View All SBIPO Previous Year Papers

5.5

4.5

7.5

2.5

None of the above

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Explanation:

- B's minimum efficiency: To calculate B's minimum efficiency, divide the actual work done by the maximum time. B's efficiency is \( \frac{60 \text{ units}}{12 \text{ hours}} = 5 \text{ units/hour} \).

- Increased Efficiency: If B works with 60% more efficiency, the new efficiency is \( 5 \times 1.6 = 8 \text{ units/hour} \).

- Time to complete 60 units at increased efficiency: \( \frac{60 \text{ units}}{8 \text{ units/hour}} = 7.5 \text{ hours} \).

- Rest Time: B has a maximum time of 12 hours. So, rest time is \( 12 - 7.5 = 4.5 \text{ hours} \).

- Answer: The correct option is Option 2: 4.5 hours .