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Direction: Read the given information and answer the following questions.
There is a building in which total of ten rooms are present in which odd numbered floor has one room and even numbered floor have two rooms. Each room is given a different number and different alphabet based on the given conditions.
Arrangement 1: The number will be allotted to each room based on this output of dice. (6,5), (1,1), (6,3), (3,5), (2,3), (4,3), (1,4), (3,4), (4,4), (1,2).
The operation will be carried out from left to right on this above output. For even numbered floor the digits in the output will be added and for odd numbered floor the digits in the output will be multiplied. First fill one room on each even numbered floor in decreasing order of the floor. Then fill the odd numbered floor in increasing order. The remaining will be filled in decreasing order of even numbered floor.
Arrangement 2: The alphabets will be allotted based on the given conditions.
E, V, I, F, A, H, R, M, T, P.
All the vowels will be placed with the odd prime numbers in decreasing order of the number and the increasing alphabet order of the vowels according to the English alphabet. Then the alphabets before the letter L according to English alphabet will be placed with the square numbers in increasing order of the number and increasing order of the letters according to the English alphabets. The remaining letters will be allotted in the increasing order of the remaining numbers and the increasing order of the remaining letters according to the English alphabet.
Arrangement 3: The letters are then placed in the linear seating arrangement in which all are facing the north direction.
The number of letters between I and A is equal to the number of persons between I and E. No vowel sits at the end of the line. The number of letters between I and E is a even prime number. Three persons sit between I and the one who lives in first floor. M sits to the immediate right of V. R sits fourth to the left of E. H sits at one of the end of the line. The one whose room is in 5th floor sits to the immediate right of the one who has an even square number.
What is the sum of the one who lives in floor 1 and the one who is to the immediate left of R?
17
18
21
20
19
- Arrangement 1: For the dice outputs:
- Even floor operations: (6+5), (1+1), (6+3), (3+5), (2+3) result in 11, 2, 9, 8, 5.
- Odd floor operations: (4×3), (1×4), (3×4), (4×4), (1×2) result in 12, 4, 12, 16, 2.
- Arrangement 2: Distribute alphabets based on conditions:
- Vowels with odd primes: 5 (E), 3 (A)
- Alphabets before L and square numbers: 4 (F), 9 (H), 16 (I)
- Remaining letters and numbers: 2 (M), 8 (P), 11 (R), 12 (T)
- Arrangement 3: Place letters in a line:
- E does not sit at the end.
- R is 4th to the left of E.
- M is to the immediate right of V.
- H is at one end.
- A, I, E conditions, ensuring prime spaces between them.
- Seventh position in line connects room 5 and a square number.
- Sum Calculation: Room 1 has number 12 (T). The number immediately left of R (M sits by 2) is 9 (H).
- Total sum: 12 + 9 = 21
- Correct Answer: Option 3: 21
By: Parvesh Mehta ProfileResourcesReport error
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