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Pipe A alone fill the tank in 24 hours and the efficiency of pipe A and B in the ratio of 5:3. If pipes A and B are opened together and at the end of each hour one-fourth of water added by A and B together in a hour is leaked from the tank, in how many hours are required to fill the tank completely?
20 Hr.
10 Hr.
8 Hr.
14 Hr.
15 Hr.
- Pipe A fills the tank in 24 hours, so its rate is 1/24 of the tank per hour.
- Efficiency ratio A:B = 5:3. Thus, B's rate = (3/5) × (1/24) = 1/40 per hour.
- Both pipes together fill (1/24 + 1/40) = (5+3)/120 = 8/120 = 1/15 of the tank per hour.
- But at the end of each hour, 1/4th of what was added is leaked. So only 3/4th remains each hour.
- Effective fill per hour = (3/4) × (1/15) = 1/20 of the tank.
- Time to fill = 20 hours.
The correct option is:
- Option:1, 20 Hr.
By: Parvesh Mehta ProfileResourcesReport error
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