The total time taken by the boat to go 39 x 39 km upstream and then return back to a certain distanc...........

Quantitative Aptitude(IBPS CL) Boats and Streams

The total time taken by the boat to go 'x' km upstream and then return back to a certain distance is 6 hours. The ratio of the speed boat in still water to the speed of the stream is 8 : 1, respectively. If the upstream distance covered is 50 km more than the downstream distance covered and the boat can cover (3x + 60) km in still water in 12 hours, then find the value of 'x'?

This questions was previously asked in

IBPS Clerk Main (8th Oct 2022)

View All IBPSCl Previous Year Papers

120 km

128 km

140 km

150 km

158 km

छोटे Courses बड़े Results

Master Boats and Streams

Prepare through Micro-courses

Try Now

Explanation:

- The speed ratio of the boat in still water to the stream is 8:1. Let's denote the speed of the stream as 's'. Therefore, the boat's speed in still water is '8s'.

- The time taken for travel is 6 hours, with the upstream distance being 50 km more than the downstream distance.

- The equation representing the boat's still water travel rate is (3x + 60) km in 12 hours. This implies the boat’s speed in still water is (3x + 60) / 12 km/h.

- Since speed in still water is '8s', equating gives: 8s = (3x + 60) / 12. This equation helps to solve for 'x'.

- Using provided information, solve the equations:

Upstream distance = x km, Downstream distance = x - 50 km.

- Applying speed and time conditions, plug these into distance = speed * time formulas.

- Option 3: 140 km works as the balance for the given conditions:

- Equating and solving the derived equations from conditions gives x = 140.

Correct Answer: Option 3 - 140 km

“”