Multiple Choice Questions

Let N be the greatest number that will divide 1305 4665 and 6905 leaving the same remainder in each ...........

Quantitative Aptitude and Numerical Ability (DRDO) (Phase-i and II) LCM, HCF

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

N = H.C.F. of (4665 – 1305), (6905 – 4665) and (6905 – 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Hence, option 1 is the correct answer.

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