Multiple Choice Questions

H C F of 4 x 27 x 3125 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is ........

Quantitative Aptitude and Numerical Ability (DRDO) (Phase-i and II) LCM, HCF

H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is

180

240

300

350

4×27×3125 = 2²×3³×55

8×9×25×7 = 2³×3²×5²×7

16×81×5×11×49 = 2⁴×3⁴×5×7²×11

Therefore, H.C.F = 22×32×5 = 180

Hence, option 1 is the correct answer.

$\inline \fn_jvn \therefore$ $\inline \fn_jvn H.C.F =2^{2}\times 3^{2}\times 5=180$

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