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The average daily wages of A, B and C is Rs 120. If B earns Rs. 40 more than C per day and A earns double of what C earns per day, the wages of A per day is
Rs. 80
Rs. 120
Rs. 160
Rs. 100
Let daily wages of C = X Then, daily wages of A = 2X and daily wages of B = X + 40 Hence, average daily wages of A, B and C = (X + 2X + X + 40) / 3 = (4X + 40)/3 Thus, (4X + 40)/3 =120
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Shekhar
Answer should be 40
shweta
answer should be 40
wages of A is double of C and after calculation we find C=80 so wages of A=80 x 2=160.
Nadineenu
answer 40
x= 40 2x= 80
Diksha garg
answer should be 40 rs.
A= 2X IF X = 40 THEN 2X = 80
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