Multiple Choice Questions on What is the HCF of 8 x5 ndash x3 x and 28 x6 1 ........ for Punjab Patwari Exam Preparation

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Multiple Choice Questions

What is the HCF of 8 x5 ndash x3 x and 28 x6 1 ........

Quantitative Aptitude (Pb Patwari) Algebra
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    What is the HCF of 8(x5 – x3 + x) and 28 (x6 + 1)?

    4(x4 – x2 + 1)

    Correct Answer

    2(x4 – x2 + 1)

    Incorrect Answer

    (x4 – x2 + 1)

    Incorrect Answer

    None of these

    Incorrect Answer
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    Explanation:

    Let f(x) = 8(x5 – x3 + x) = 4 × 2 × x (x4 – x2 + 1)
    and g(x) = 28 (x6 + 1) = 7 × 4[(x2)3 + (12)3]
    = 4 × 7 (x2 + 1) (x4 – x2 + 1)
    ∴   HCF of  [f(x), g(x)]  =  4(x4 – x2 + 1)

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