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Study the following table carefully and answer the questions that follow: The table shows the individual scores of 5 players – A, B, C, D and E in 4 difference matches. (Though some values are missing) The missing values in column for match 1 are the lowest scores in that match. Also, the missing values in column for match 3 except the scores of B are the lowest scores in that match.
What is the total score of A and C together?
196
204
200
191
In Match 1: Total of missing value = 150 – (27+36+35) = 52 Given that the missing value is the lowest in Match 1. Then in match 1 the missing values should be Score of B in match 3 = 121 – (26+49+20) = 26 Now we know Score of B in Match 3. So Match 3: Proceed similar as above in Match 1, so both the missing values in Match 3 are 12. Score of A in match 4 = 87 – (27+32+12) = 16 Score of D in match 2 = 93 – (35+12+18) = 28 Score of E in match 4 = 107 – (26+33+13) = 35 So total in match 4 = 16 + 20+ 22 + 18 + 35 = 111 So total in match 2 = 111 + 57 = 168 So, Score of C in match 2 = 168 – (32+49+28+33) = 26 So, last total score of C = 36 + 26 + 29 + 22 = 113
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