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12 children and 15 men complete a certain piece of work in 7 days. If each child takes twice the time taken by a man to finish the work, in how many days will 14 men finish the same work?
12days
11 1/3days
10 1/2days
11days
1Children =2men 12children=6men Then 12C+15M =6M+15M ==>21M 21M—–7 14M—–?==> (21*7)/14=10 1/2days.
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