The population of a city increases 5 annually in compounded manner yearly compounding The present po...........

Quantitative Aptitude (CHSL) Percentage

The population of a city increases 5% annually in compounded manner (yearly compounding). The present population of this

city is 93051. The population of this city 2 years ago was:

This questions was previously asked in

SSC CHSL 31st May 2022 Shift-1

84400

84000

88000

88400

- To find the population of the city two years ago, we need to account for the 5% annual compound growth.

- The formula used is: \( P = \frac{P_0}{(1 + r)^n} \).

- Here, \( P_0 \) is the current population (93051),

- \( r \) is the growth rate (0.05),

- \( n \) is the number of years (2).

- Plugging the numbers in \( P = \frac{93051}{(1.05)^2} \).

- This simplifies to \( P \approx 93051 / 1.1025 \approx 84400 \).

- Option 1: 84400 - Correct

- Option 2: 84000 – Not correct, slightly low.

- Option 3: 88000 – Too high.

- Option 4: 88400 – Too high.

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