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There are 5 consecutive odd numbers .If the difference between the square of the average of the first two odd numbers and square of the average of the last two odd numbers is 492 ,what is the smallest odd number ?
35
40
37
34
Solution: Five consecutive odd numbers = x , x+2, x +4 , x+6 and x +8 Now , [(x+6+x+8) /2]2 – [(x+x+2)/2]2 = 492 =>x= 444/12 = 37 Smallest odd number = 37
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