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2 groups A and B contain some people each. Efficiencies of all people in group A is same while that in group B is same. 3 workers from group A and 6 from group B can complete the work in 20 days. 8 workers from group A and 4 from group B can complete the work in 10 days. Find the number of days in which 1 person from each group can complete the work working together.
96 days
72 days
90 days
54 days
Explanation: The question is same as 3 m and 6 w complete work in 20 days. And 8 m and 4 w complete work in 10 days. So 3A + 6B = 20 => 60 A + 120B = 1 And 8A + 4B = 10 => 80 A + 40B = 1 So 60 A + 120B = 80 A + 40B 80B = 20A B = A/4 So – 8A + 4 * A/4 = 10 or 9A = 10 So 9 workers of group A can complete work in 10 days Required to find A + B = A + A/4 = 5A/4 So 9 * 10 = 5/4 * x Solve, x = 72 days
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