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The difference of two numbers is 14. Their LCM and HCF are 441 and 7. Find the two numbers ?63
63 and 49
64 and 48
62 and 48
64 and 49
Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y
Difference = 14 => 7x - 7y = 14 => x - y = 2
product of numbers = product of their hcf and lcm => 7x * 7y = 441 * 7 => x * y = 63
Now, we have x * y = 63 , x - y = 2 => x = 9 , y = 7
The numbers are 7x and 7y => 63 and 49
Hence, option 1 is the correct answer.
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