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In questions based on Data Sufficiency, candidates are given a piece of information followed by a few conditions and then a few options where they have to answer which of the given conditions shall be necessary to answer the question.
As complicated as it may seem, the data sufficiency questions may be time taking at times because of their length and multiple options. Candidates need to ensure that they do not panic seeing the length of the question and guess the answer to the questions.
There are a few tips and tricks which can be followed to solve the data sufficiency questions. Candidates can refer to these tips given below:
1. What is perimeter of the rectangle ?
I. Perimeter of square is 84 cm and length of rectangle is equal is equal to side of square.
II. The length of rectangle is 40% more than the breadth of rectangle.
Solution:
From I, Side of square = 84/4 = 21cm
length of rectangle = 21
from II, let of breadth of rectangle = 5x
and length = 5x * 140/100 = 7x
from I and II both,
breadth of rectangle = 21/7x * 5x = 15
perimeter of rectangle = (21 + 15)2 = 72 cm
Both statement are required to find the answer.
2. What is the length of train ?
I. The train crosses a 220 meters long platform in 15 seconds.
II. The train crosses a person walking in opposite direction in 6 seconds.
From I, Let length of train = x
speed of train = y
x + 220/y = 15
From II, Let speed of man = z km/hr
x/y + z = 6
Both statement I and II are not sufficient to calculate the answer.
3. What is the rate of interest ?
I. Rs. 4000 becomes rs.5200 in 2 years when invested at simple interest.
II. The same sum is invested in CI and SI for 2 years at same rate of interest and difference between CI and SI is rs.90.
From I, Sum = 4000
2 years interest = 5200 – 4000 = 1200
1 years interest = 1200/2 = 600
rate of interest = 600/4000 * 100 = 15%
from II, P = 4000
difference = 90
90 = 4000 * R^2/1000^2
R = 15%
either I or II is sufficient.
4. What is the speed of boat in still water ?
I. Boat covers 150 km in upstream speed in 10 hours.
II. Ratio of speed of downstream and upstream is 5 : 3.
From I, Upstream speed = 150/10 = 15 km/hr
from II, Let downstream speed = 5x
upstream speed = 3x
from both I and II,
downstream speed = 15/3x * 5x = 25 km/hr
speed of boat = 25 + 15 /2 = 40/2 = 20 km/hr
5. In how many days B alone can do the work ?
I. A and B together can complete a work is 18 days.
II. B and C together can complete the same work in 24 days.
Alone statement I and II can not find answer
from both statement I and II together
LCM of 18 and 24 = 72
efficiency of A and B = 72/18 = 4
efficiency of B and C = 72/24 = 3
Here , we can not find individual efficiency so,
from both statement I and II we can not calculate the answer.
6. What is the area of square ?
I. The perimeter of square is 36 cm.
II. The area of rectangle is 96 cm^2 and side of square is 3 cm less than length of rectangular.
From I, perimeter of square is 36 cm.
side of square = 36/4 = 9 cm
area of square = 9 * 9 = 81 cm^2
From II, Area of rectangle = 96 cm^2
only from II we can not find the answer.
only statement I is sufficient.
7. How much profit earned selling a table ?
I. The ratio of cost price and marked price of the table is 5 : 8. After giving some discount profit percent occurred is 28%.
II. The shopkeeper is given 20% discount on MP and selling price of the table is rs.320.
From I , Let CP of table = 5x
MP = 8x
profit = 28%
From II, SP = 320
discount = 20%
MP = 320/4 * 5 = 400
both From I and II,
MP = 400
CP = 400/8 * 5 = 250
profit = 320 – 250 = 70
Both I and II are sufficient to find answer.
8. What is profit share of C ?
I. A and B start the business with capital of rs.8000 and rs.10000 respectively.
II. After 4 months C joined the business with capital of rs.6000 and total profit at the end is rs 2200.
From I, A and B invested rs.8000 and rs.10000 respectively.
from II, total profit = rs. 2200
C invested 6000 for 8 months
Both from I and II,
Profit sharing ratio of A, b and C = (8000 * 12) : (10000 * 12) : (6000 * 8)
= 4 : 5 : 2
profit of C = 2200 * 2/11 = 400
Both statement I and II is required to find answer.
9. What is the age of the mother of Rohit ?
I. The age of Rohit’s father is 3 times more than age of Rohit. After 4 years the ratio of age of Rohit and his father becomes 1: 3 and the age of mother is 4 years less than the age of his father.
II. The ratio of age of Rohit and his mother is 2 : 7 and before 4 years the age of Rohit and his mother 1 : 6.
From I, Let the age of Rohit = x
the age of his father = 3x + x = 4x
After 4 years,
x + 4/ 4x + 4 = 1/3
3x + 12 = 4x + 4
x = 8
age of his father = 4x = 4 * 8 = 32
age of his mother = 32 – 4 = 28
From II, Let the age of Rohit = 2x
the age of his mother = 7x
before 4 years,
2x – 4/ 7x – 4 = 1/6
12x – 24 = 7x – 4
5x = 20
x = 4
age of his mother = 7 * 4 = 28 years
Answer- Either statement I or statement II is sufficient.
10. How much marks scored by Rinu ?
I. Rinu scored 32% and failed by 48 marks.
II. She scored 49% which is 54 more marks than pass marks.
Either I or II we can not calculate the answer.
Both statement I and II,
32% + 48 = 49% – 54
17% = 102
1% = 6
pass marks = 32% + 48 = 192 + 48 = 240 marks
Both I and II is required to get answer.
By: Munesh Kumari ProfileResourcesReport error
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