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If the ages of A and C are added to twice the age of B, the total becomes 59. If the ages of B and C are added to thrice the ageof A, the total becomes 68 and if the age of A is added to thrice the age of B and thrice and age Of C, the total becomes 108. What is the age of A?
18 years
15 years
12 years
20 years
Solution: A+C+2B=59–1 B+C+3A=68–2 A+3B+3C=108–3 Multiply eqn 2 by 3 and subtract 3 (3B+3C+9A=204) – (A+3B+3C=108) 9A-A=204-108=96 A=12 yrs.
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Neha Choudhary
Why did we multiply equation 2 By 3
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