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Three numbers are in the ratio 6: 8: 10 and their LCM is 1200. Their HCF is
40
80
10
200
Solution: Let the numbers be 6x, 8x and 10x.
Then: Let the numbers be 6x, 8x and 10x. Then, their L.C.M. = 120x. So, 120x = 1200 or x = 10. The numbers are (6 x 10), (8 x 10) and (10 x 10) i.e. 60, 80, 100 Hence, required H.C.F. = 10.
By: Parvesh Mehta ProfileResourcesReport error
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