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Select the set in which the numbers are related in the same way as are the numbers of the following set.
(NOTE : Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13- Operations on 13 such as adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is NOT allowed)
(8, 388, 18)
(11 , 137, 4)
(15, 230, 2)
(3, 51, 7)
(10, 118, 9)
(14, 221, 5)
Let’s break it down.
First, look at the original sets:
(11, 137, 4)
We're told not to break the numbers apart, so think: what operation links the first and third numbers to make the second? Try plugging things in:
- 8 × 18 = 144 (not 388)
- 8 + 18 = 26
- 8 × something (but not 18) = 388
- 8 × 18 + something? Let's check: 8 × 18 = 144. 388 – 144 = 244. Not a direct relation.
Reverse:
- 388 ÷ 8 = 48.5
- 388 ÷ 18 = 21.555
- 388 – 8 = 380
- 388 – 18 = 370
Maybe try:
Is 388 divisible by 8 or 18? No.
Try squaring or similar:
- 8² = 64
- 18² = 324
Then, 8² + 18² = 64 + 324 = 388
—this fits!
Now, (11, 137, 4)
11² = 121, 4² = 16. 121 + 16 = 137
—Bingo, same relationship.
They’re using: (a, b, c) ? a² + c² = b
Now, check your options:
Option 1: (15, 230, 2)
15² = 225, 2² = 4, 225 + 4 = 229 Not 230.
Option 2: (3, 51, 7)
3² = 9, 7² = 49, 9 + 49 = 58 Not 51.
Option 3: (10, 118, 9)
10² = 100, 9² = 81, 100 + 81 = 181 Not 118.
Option 4: (14, 221, 5)
14² = 196, 5² = 25, 196 + 25 = 221
This follows the same pattern.
So, your logic is straight on point here.
Correct Answer:
Option 4 (14, 221, 5)
- The rule: a² + c² = b, do not split numbers into digits.
- Only option 4 fits.
- The question is all about recognizing the sum of perfect squares.
Simple as that.
By: Parvesh Mehta ProfileResourcesReport error
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