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Mixture 1 contains 20% of water and mixture 2 contains 35% of water. 10 parts from 1st mixture and 4 parts from 2nd mixture is taken and put in a glass. What is the percentage of water in the new mixture of glass?
17 (5/7)%
24 (2/7)%
28 (1/5)%
24 (1/7)%
Water in new mixture from 1st mixture = (20/100) * 10 = 2 parts Water in new mixture from 2nd mixture = (35/100) * 4 = 7/5 parts Required % =[ [2+ (7/5)]/(10+4)] * 100 = (17/70)*100 = 24(2/7)
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