Explanation:

To solve the problem, let's calculate how much work is done each day:

- A's rate of working: 1/8 of the work per day.

- B's rate of working: 1/16 of the work per day.

- C's rate of working: 1/12 of the work per day.

The pattern repeats every three days, so let's calculate the work done in the first three days:

- Monday (A): 1/8

- Tuesday (B): 1/16

- Wednesday (C): 1/12

Total work done in 3 days:

$$\frac{1}{8}+\frac{1}{16}+\frac{1}{12}=\frac{6}{48}+\frac{3}{48}+\frac{4}{48}=\frac{13}{48}$$

Now, let's find out how many such 3-day cycles are needed to complete the work:

- Work done in 6 days (first two cycles):

$$2\times \frac{13}{48}=\frac{26}{48}$$

- Seventh day (A): 1/8

Work done by A on Thursday: $$\frac{1}{8}=\frac{6}{48}$$

Adding this on the seventh day:

$$\frac{26}{48}+\frac{6}{48}=\frac{32}{48}$$

- Eighth day (B): 1/16

Work done by B on Friday: $$\frac{3}{48}$$

Adding this on the eighth day:

$$\frac{32}{48}+\frac{3}{48}=\frac{35}{48}$$

- Ninth day (C): 1/12

Work done by C on Saturday: $$\frac{4}{48}$$

Adding this on the ninth day:

$$\frac{35}{48}+\frac{4}{48}=\frac{39}{48}$$

Finally, on the tenth day (A), he completes:

$$\frac{6}{48}$$

Total work by tenth day:

$$\frac{39}{48}+\frac{6}{48}=1$$

- The work is finished on the tenth day.

Review of Statements

- Statement 1: The work will be finished on Thursday. (Incorrect, it finishes on the following Monday)

- Statement 2: The work will be finished in 10 days. (Correct)

Conclusion:

- The correct option is: 2, 2 only.