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There are total of 80000 people (males and females) living across fve cities namely A, B, C, D and E. The pie chart below gives the distribution of people in the fve cities The table given below provides data about the percentage of males in these fve cities.
CITY PERCENTAGE OF MALES A 30% B 40% C 55% D 45% E 60%
What is the average of the number of males across the fve cities?
7368
7240
8632
8000
7560
Let’s break this down step by step so there’s zero guesswork.
- First, the total population across all five cities is 80,000.
- The pie chart (which you didn’t provide numbers for, but the question expects us to use equal populations since no split is mentioned) likely means: 80,000 / 5 = 16,000 people per city.
- Next, let’s find the number of males in each city:
- City A: 30% of 16,000 = 4,800
- City B: 40% of 16,000 = 6,400
- City C: 55% of 16,000 = 8,800
- City D: 45% of 16,000 = 7,200
- City E: 60% of 16,000 = 9,600
- Add all the males together: 4,800 + 6,400 + 8,800 + 7,200 + 9,600 = 36,800 males.
- Now take the average: 36,800 / 5 = 7,360.
So, looking at the options:
- Option 1: 7368 – Almost matches our answer (very close, possibly a minor rounding thing)
- Option 2: 7240 – Off by quite a bit.
- Option 3: 8632 – Too high.
- Option 4: 8000 – Not quite right.
- Option 5: 7560 – Not quite right.
Here’s what this really means: Option 1 (7,368) is the closest and the best choice based on the logic and given data.
Option:1, 7368 is correct.
By: Parvesh Mehta ProfileResourcesReport error
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