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A wire of resistance R is cut into four equal parts. These parts are then connected in parallel. If the equivalent resistance of this
combination is R', then the ratio R/R is :
1/16
1/4
4
16
- Let’s break down the problem:
- The original wire has resistance \( R \).
- Cutting it into four equal pieces means each piece has length \( l/4 \).
- Resistance of each new piece \( r = R/4 \) (since resistance is directly proportional to length).
- These four pieces are then connected in parallel.
- Equivalent resistance for n equal resistors (each \( r \)) in parallel: \( R' = r/n = (R/4)/4 = R/16 \).
- So, the required ratio \( R/R' = R/(R/16) = 16 \).
- Option 4 (16) is the correct answer.
Option explanations:
- Option 1 (1/16): This would be if you did R'/R, not R/R'.
- Option 2 (1/4): Not relevant for parallel combination of four.
- Option 3 (4): Happens for series combination.
- Option 4 (16): Correct for parallel combination after cutting.
By: Parvesh Mehta ProfileResourcesReport error
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