Explanation:

- Statement 1: If R is reflexive, then R^-1 is also reflexive.

- Reflexivity implies every element is related to itself (`(a, a)` exists).

- For R^-1, `(a, a)` exists as well because inversion doesn't affect reflexivity.

- Statement 2: If R is symmetric, then R^-1 is also symmetric.

- Symmetry implies if `(a, b)` exists, then `(b, a)` exists.

- The inverse simply swaps the pair, preserving symmetry.

- Statement 3: If R is transitive, then R^-1 is also transitive.

- Transitivity implies if `(a, b)` and `(b, c)` exist, then `(a, c)` must exist.

- The inverse requires `(c, b)` and `(b, a)` to imply `(c, a)`, which is not guaranteed.

- Correct Option: Option 1: 1 and 2 only