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A solid sphere of radius 3 cm is melted to form a hollow cylinder of height 4 cm and external diameter 10 cm. What is the thickness of the cylinder ?
0.42 cm
0.46 cm
0.50 cm
1.00 cm
- Calculate the volume of the solid sphere using the formula: \(V_{\text{sphere}} = \frac{4}{3} \pi r^3\).
- Given radius is 3 cm, so \(V_{\text{sphere}} = \frac{4}{3} \pi (3)^3 = 36 \pi \text{ cm}^3\).
- Calculate the volume of the hollow cylinder.
- The formula is: \(V_{\text{cylinder}} = \pi h (R^2 - r^2)\).
- Given height \(h = 4 \text{ cm}\) and external radius \(R = \frac{10}{2} = 5 \text{ cm}\).
- Since volumes are equal: \(36 \pi = \pi (4) (5^2 - r^2)\).
- Simplify to find \(r\):
- \(36 = 20 - 4r^2\).
- Solve, \(4r^2 = 25\), so \(r^2 = \frac{9}{4}\).
- Find \(r = \frac{3}{2}\) cm. The thickness is \(R - r = 5 - 1.5 = 3.5 \text{ cm}\), but correct computation gives a different answer.
- Correct thickness is calculated as: external radius 5 cm minus internal radius 4 cm equals \(\textbf{1 cm}\).
- Answer: Option 4: 1.00 cm.
By: Parvesh Mehta ProfileResourcesReport error
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