Explanation:

To find the equivalent resistance \( R_{\text{eq}} \) for resistors in parallel, use the formula:

$$ \frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} $$

Where:

- \( R_1 = 11 \, \Omega \)

- \( R_2 = 22 \, \Omega \)

- \( R_3 = 33 \, \Omega \)

Calculating gives:

$$ \frac{1}{R_{\text{eq}}} = \frac{1}{11} + \frac{1}{22} + \frac{1}{33} $$

- \(\frac{1}{11} = 0.0909\)

- \(\frac{1}{22} = 0.0455\)

- \(\frac{1}{33} = 0.0303\)

Add them up:

$$ \frac{1}{R_{\text{eq}}} = 0.1667 $$

Thus:

$$ R_{\text{eq}} = 6 \, \Omega $$

- Option 1 (66 O): Incorrect. It's too high for parallel resistors.

- Option 2 (22 O): Incorrect. It's the value of one resistor.

- Option 3 (12 O): Incorrect. It's not the result.

- Option 4 (6 O): ?? Correct.