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In a vessel, milk and water are in a ratio of 3 : 5. In the second vessel, the milk and water are in the ratio of 3 : 2. In what ratio should these two mixtures be mixed to form a new mixture in which the milk and water are in the ratio 2 : 3?
1 : 8
6 : 1
7 : 1
8 : 1
None of these
To solve the problem, we need to determine the amounts of milk in each vessel first, and then find out how to mix them to get the desired ratio in a new mixture.
- First Vessel:
- Ratio of milk to water is 3:5.
- Milk part = 3/8 of the mixture.
- Second Vessel:
- Ratio of milk to water is 3:2.
- Milk part = 3/5 of the mixture.
To find the required ratio in which these mixtures are to be mixed to achieve a milk to water ratio of 2:3 (which means milk part = 2/5 of the mixture):
- We balance the equation based on the milk content from both vessels to equal the new target mixture.
$$
\frac{3}{8}x + \frac{3}{5}y = \frac{2}{5}(x + y)
- Simplifying the equation leads to:
\frac{3}{8}x + \frac{3}{5}y = \frac{2}{5}x + \frac{2}{5}y
- Solving for x and y gives the mixing ratio as 8:1.
Thus, the option 4 with the ratio 8:1 is the correct one.
Answer: Option 4 - 8 : 1
By: Parvesh Mehta ProfileResourcesReport error
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