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Pipe P can fill a tank in 44 minutes and Pipe R can fill a tank in 33 minutes. If the pipes are opened alternatively for 2 minutes each starting with pipe P. Then, in how much time the tank is filled?
31 minutes
38 minutes
35 minutes
30 minutes
23 minutes
- Pipe P: Fills the tank in 44 minutes, so in 1 minute, it fills \( \frac{1}{44} \) of the tank.
- Pipe R: Fills the tank in 33 minutes, so in 1 minute, it fills \( \frac{1}{33} \) of the tank.
- Cycle Duration: Every 4-minute cycle consists of 2 minutes of Pipe P and 2 minutes of Pipe R.
- Amount Filled in 4 Minutes:
- 2 minutes of Pipe P: \( 2 \times \frac{1}{44} = \frac{1}{22} \)
- 2 minutes of Pipe R: \( 2 \times \frac{1}{33} = \frac{2}{33} \)
- Total: \( \frac{1}{22} + \frac{2}{33} = \frac{3}{66} + \frac{4}{66} = \frac{7}{66} \)
- Total Time Needed to Fill the Tank:
- After nine 4-minute cycles (36 minutes), \( 9 \times \frac{7}{66} = \frac{63}{66} \) of the tank is filled.
- Pipe P runs for another 2 minutes: \( \frac{1}{22} = \frac{3}{66} \) fills the rest.
- Total Time to Fill the Tank: 36 minutes (9 cycles) + 2 minutes = 38 minutes.
- Correct Answer: Option 2: 38 minutes
By: Parvesh Mehta ProfileResourcesReport error
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