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Two vessels contain milk and water mixed respectively in the ratio 3 : 5 and 5 : 3. Find the ratio in which these are to be mixed to get a new mixture in which the ratio of milk to water is 3 : 4.
11 : 3
7 : 3
8 : 5
10 : 9
11 : 6
Let’s break this down:
- First vessel: Ratio 3:5 (milk : water).
Milk = 3/8, Water = 5/8.
- Second vessel: Ratio 5:3 (milk : water).
Milk = 5/8, Water = 3/8.
- Want: Final mixture with ratio 3:4 (milk : water), i.e., Milk = 3/7, Water = 4/7.
Here's how you set it up:
- Let’s say x liters from vessel 1, y liters from vessel 2.
- Milk in final: (3/8)x + (5/8)y.
- Water in final: (5/8)x + (3/8)y.
- Set up the ratio:
$$
\frac{\frac{3}{8}x + \frac{5}{8}y}{\frac{5}{8}x + \frac{3}{8}y} = \frac{3}{4}
Cross-multiplied:
4(3x + 5y) = 3(5x + 3y) \\
12x + 20y = 15x + 9y \\
11y = 3x \\
x/y = 11/3
- That’s option 1: 11 : 3.
- Option 2: 7 : 3 — Not correct, does not match calculation.
- Option 3: 8 : 5 — No.
- Option 4: 10 : 9 — Also not matching.
- Option 5: 11 : 6 — Close but not correct.
Option 1 (11 : 3) is the answer.
By: Parvesh Mehta ProfileResourcesReport error
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