send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A man borrowed a total amount of Rs. 36,000. A part of it is on SI at 12% per annum and the remaining on SI at 10% per annum. If at the end of 2 years, he paid in all 43920 to settle the loan amount, find the amount that was borrowed at 12% per annum?
19000
20000
18000
17000
16000
To solve this, let's use a simple calculation:
- Let the amount taken at 12% be X.
- Thus, the amount taken at 10% will be 36,000 - X.
- Interest from part at 12% after 2 years: X×12100×2=0.24X
- Interest from part at 10% after 2 years: (36,000−X)×10100×2=0.2×(36,000−X)
- Total final amount paid to settle the loan is 43,920.
Now, let's solve:
- Total interest = 43,920 - 36,000 = 7,920
- Equation: 0.24X+0.2(36,000−X)=7,920
Simplifying,
- 0.24X+7,200−0.2X=7,920
- 0.04X=720
- X=7200.04=18,000
- ? Correct Answer: Option 3 - Rs. 18,000
Report error
Access to prime resources