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In these question, two equations (I) and (II) are given. You have to solve both the equations and answer accordingly:
(I) x2 – 20x + 99 = 0
(II) y2 – 16y + 63 = 0
x > y
x ≥ y
y > x
y ≥ x
x = y or the relationship between x and y cannot be established.
Let's find the values of x and y:
- Equation (I): x2−20x+99=0
- Factorizing gives (x−9)(x−11)=0.
- So, x=9 or x=11.
- Equation (II): y2−16y+63=0
- Factorizing gives (y−7)(y−9)=0.
- So, y=7 or y=9.
- Now, compare:
- x=9 and y=7 or y=9.
- x=11 (always greater than y=7 or y=9).
- Based on this comparison, Option 2: x = y is correct.
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