Explanation:

Let’s break this down step by step:

- The question: \(2^3 \times 4^2 \div 8 = (2)^?\)

- First, calculate each part:

- \(2^3 = 8\)

- \(4^2 = 16\)

- So, \(8 \times 16 = 128\)

- Now, divide by 8:

- \(128 \div 8 = 16\)

- So we have: \( (2)^? = 16 \)

- What power of 2 gives 16?

- \(2^4 = 16\)

- So the correct answer is 4 (Option 3).

Option:3, 4 is right.

The other options:

- 1, 3 (\(2^3 = 8\)) — Not 16.

- 2, 5 (\(2^5 = 32\)) — Too high.

- 4, 6 (\(2^6 = 64\)) — Way too high.

- 5, 2 (\(2^2 = 4\)) — Too low.

What this really means: breaking exponents down, matching both sides, Option 3 hits the spot—simple as that.