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What is number of Wooden toys purchased by female on Wednesday if ratio of Wooden toys sold to female to that of male on Wednesday is 7: 3? (if toys are sold only to male and female)
98
84
104
78
91
Alright, let’s get practical with this one.
- The question: We’re told the ratio of Wooden toys sold to females vs. males on Wednesday is 7:3.
- That means out of every 10 toys, 7 go to females, 3 to males.
- The options are 98, 84, 104, 78, 91, and you think it's 91.
Now, to solve, you’d need the total number of Wooden toys sold on Wednesday (let’s call it X). The number sold to females would then be (7/10) of X.
But—none of these numbers matter unless we know X.
Let’s test each option, assuming the number given is the number sold to females:
- If 98 were sold to females: Total would be (98 * 10/7) = 140
- If 84: (84 * 10/7) = 120
- If 104: (104 * 10/7) = 148.57 (not a whole number, can’t be)
- If 78: (78 * 10/7) = 111.43 (not whole)
- If 91: (91 * 10/7) = 130
Now check if the male share is a whole number for these plausible options:
- For 91: Males get (3/10) * 130 = 39
- For 98: Males get (3/10) * 140 = 42
- For 84: (3/10) * 120 = 36
Here's the thing— all three (91, 98, 84) give whole numbers for both groups and keep the 7:3 ratio.
But—let's check which fits 7/10 exactly:
- (91 / (91 + 39)) = 91 / 130 = 0.7
- (98 / 140) = 0.7
- (84 / 120) = 0.7
So, all fit the ratio—meaning multiple answers *could* technically work, but, based on standard question patterns, option:1 (98) usually fits textbook setups because 140 is a nice round total. However—
Based on your answer—option:5 (91)—
The best fit, considering convention, is:
Option 1: 98
This one keeps everything whole, keeps ratios tidy, and is the most likely pick if you had to choose one. Which, let’s face it, you do.
By: Parvesh Mehta ProfileResourcesReport error
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