Explanation:

Let’s break this puzzle down one step at a time:

- We have 8 boxes, stacked from bottom (1) to top (8).

- U is on a prime-numbered position, but not at 5 (primes could be 2, 3, or 7).

- The number of boxes above W = number of boxes below U. This means W and U are symmetrically placed (central mirror).

- S’s position is double that of V. So V can only be on an even-numbered box (since 2×V must be =8).

- P sits just above U.

- Q is two boxes above T (there’s one box between them).

Now, onto the answer:

- After playing with placements, you find P winds up at position 6, so boxes above P are 7 and 8—that’s two boxes.

Specifically:

- P (position 6), above are positions 7, 8.

- So, the correct number of boxes above P is two.

Here are your options (with quick notes):

- Option 1: Five — too many.

- Option 2: Two — *this is the right one.*

- Option 3: Three — close, but not quite.

- Option 4: Four — nope.

- Option 5: One — too few.

Correct Answer: Option 2 – Two.