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The sum of the perimeter of the rectangle and circle is 138 cm. The ratio between the length of the rectangle and the radius of the circle is 10: 7. If the breadth of the rectangle is 5/14 times the radius of the circle. Then, find the area of the rectangle (in sq. cm)?
64
100
120
140
125
Let's break down the problem:
- Let the radius of the circle be r.
- Length (L) of rectangle = 10/7 × r
- Breadth (B) of rectangle = 5/14 × r
- Perimeter of rectangle = 2(L + B)
- Perimeter of circle = 2pr
- Sum of both perimeters = 2(L + B) + 2pr = 138
Substitute values:
- 2[(10/7)r + (5/14)r] + 2pr = 138
- Calculate inside bracket: (20/14)r + (5/14)r = (25/14)r
- 2 × (25/14)r = (50/14)r ˜ 3.571r
Full equation:
- 3.571r + 6.28r = 138 (since p ˜ 3.14)
- 9.851r = 138 ? r ˜ 14
Now, area of rectangle = L × B = (10/7)r × (5/14)r = 50/98 × r² = 25/49 × r²
Plug in r ˜ 14:
- r² = 196
- Area ˜ 25/49 × 196 = 100
Option 2 - 100 is correct.
Explanation of statements & options:
- The ratio links length and radius, so length is a multiple of radius.
- Breadth is also tied to radius.
- We're just solving for perimeter sums, substituting ratios, and calculating area.
- Other options don't fit after plugging values found.
So, 100 sq. cm, Option 2, is the correct answer!
By: Parvesh Mehta ProfileResourcesReport error
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