Explanation:

Let's solve stepwise with all necessary explanations:

- Start by letting the amount of milk in 'A' = x, water = y, with x + y = 45.

- Given milk is 80% of water ? x = 0.8y.

- So, 0.8y + y = 45 ? 1.8y = 45 ? y = 25, x = 20.

- Suppose 't' liters of milk and 't' liters of water are taken out from 'A' (since it's said "same quantity").

- These '2t' liters are added to 4 liters of honey in 'B' to make mixture 'P'.

- Mixture 'P' has (t milk + t water + 4 honey) liters, and 40% of this is water:

- Water in P = t; Total volume in P = 2t + 4

- 40% of (2t + 4) = t ? 0.4(2t + 4) = t ? 0.8t + 1.6 = t ? 1.6 = 0.2t ? t = 8

Now, total quantity taken out from 'A' = 2t = 16 liters

Original quantity in 'A' = 45 liters

Percentage = (16/45) × 100 ˜ 35.56%

- So, it's between 32% and 36% (Option 3).

Option 1: 24%-28% is too low

Option 2: 28%-32% is too low

Option 3: 32%-36% is correct

Option 4 & 5: Values are too high

Correct Answer:

Option 3: Between 32% to 36%