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Sum of the length and width of a rectangle (R1) is 78 cm and of rectangle (R2) is 52 cm. What is the area of a square whose side is 1/4th of the difference of the perimeter of R1 and R2?
144
169
256
225
None of these
- The sum of the length and width of rectangle R1 is 78 cm. Therefore, its perimeter is 2 × 78 = 156 cm.
- The sum of the length and width of rectangle R2 is 52 cm. Therefore, its perimeter is 2 × 52 = 104 cm.
- The difference in the perimeters of R1 and R2 is 156 - 104 = 52 cm.
- A square’s side is 1/4th of this difference: 52 / 4 = 13 cm.
- The area of this square is side × side = 13 × 13 = 169 square cm.
Therefore, the correct option is:
- Option 2: 169
By: Parvesh Mehta ProfileResourcesReport error
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