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Directions : Study the following information carefully and answer the questions given below.
Twelve persons are born on three different dates 5, 12, 21 of four different months viz. March, May, September and November. Only one person is born on one date of a month. J was born on 5 of a month having 30 days. Only three persons were born between J and H. H does not born on an even date of a month. As many as persons born after H as born before A. Five persons born between A and D. Only two persons born between F and E. C born on an even date but immediately after K. Six person born between C and B. E born immediately before B. M born on an even date after L but before G.
In a certain code, numbers from (0-9) are coded as four alphabets i.e. ‘0389’ is coded as ‘AACD’, ‘146’ coded as ‘ABA’, then how is ‘ 257’ coded?
CBA
CDA
BAC
AAD
BCB
Here is the explanation of the given statements and options:
- Twelve persons are born on 5, 12, and 21 of March, May, September, and November.
- J is born on 5 of a month with 30 days. This means J is born on 5th September or 5th November.
- Three persons are between J and H; H isn't born on an even date.
- The number of people after H is equal to the number before A.
- Five persons separate A and D.
- Two persons are between F and E.
- C is born on an even date immediately after K.
- Six persons are between C and B.
- E is born immediately before B.
- M is born on an even date after L but before G.
In the coding, numbers are translated as follows:
- 0 = A
- 1 = B
- 4 = B
- 6 = A
- '0389' becomes 'AACD' and '146' becomes 'ABA'.
- We need to understand the pattern: similar numbers get similar codes.
For '257':
- 2 = B
- 5 = C
- 7 = B
The correct coding is 'BCB', matching Option 5.
.
By: Parvesh Mehta ProfileResourcesReport error
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