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In a bag which contains 40 balls, there are 18 red balls and some green and blue balls. If two balls are picked up from the bag without replacement, then the probability of the first ball being red and second being green is 3/26. Find the number of blue balls in the bag.
16
12
10
14
8
- You have a total of 40 balls, 18 of which are red.
- Let the number of green balls be G, and the number of blue balls be B.
- Since 40 = 18 + G + B, it follows that G + B = 22.
- The probability of picking a red ball first is 18/40.
- Without replacement, the probability of picking a green ball second is G/39.
- This can be represented by the equation: (18/40) * (G/39) = 3/26.
Solving for G:
- Simplify: (18/40) * (G/39) = 3/26.
- Multiply through: 18G/1560 = 3/26.
- 18G = 180.
- G = 10.
- Given that G + B = 22, we have 10 + B = 22, so B = 12.
- The number of blue balls is 12.
- Correct Answer: Option 2, 12
By: Parvesh Mehta ProfileResourcesReport error
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