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A, B and C have certain number of chocolates in the ratio of 3 : 2 : 5. If A takes 10 chocolates from B and 20 chocolates from C, the ratio of the chocolates of B and C becomes 1 : 3. What is the total number of chocolates they have initially?
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- A, B, and C have chocolates in the ratio 3:2:5.
- Let the number of chocolates with A, B, and C be 3x, 2x, and 5x respectively.
- A takes 10 chocolates from B and 20 from C.
- B's chocolates become 2x - 10 after A takes 10 chocolates.
- C's chocolates become 5x - 20 after A takes 20 chocolates.
- The ratio of chocolates between B and C becomes 1:3.
- Hence, (2x - 10)/(5x - 20) = 1/3.
- Solving the equation: 3(2x - 10) = 1(5x - 20)
- This leads to: 6x - 30 = 5x - 20
- Simplifying gives: x = 10.
- So, total chocolates initially = 3x + 2x + 5x = 10x = 100.
- Option 3: 100 is correct.
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By: Parvesh Mehta ProfileResourcesReport error
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