The age of the mother 4 years ago was 6 times the age of her son at that time The age of the mother ...........

Quantitative Aptitude(IBPS CL) Problems based on Ages

The age of the mother 4 years ago was 6 times the age of her son at that time. The age of the mother after 6 years will be 8/3 times the age of the son at the time. Find the difference between the mother's age after 2 years and the present age of the son.

This questions was previously asked in

IBPS Clerk Main (8th Oct 2022)

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2 : 3

3 : 2

4 : 1

5 : 2

6 : 5

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Explanation:

Correct option:3

Solution:

Mother's age 4 years ago = 6 * (Son's age 4 years ago)
Mother's age after 6 years = (8/3) * (Son's age after 6 years)
Let the age of son 4 years ago = x years
Mother's age 4 years ago = 6x
Son's age after 6 years = (x + 10)
Mother's age after 6 years = (6x + 10)
ATQ (6x + 10) = (8/3) * (x + 10)
18x + 30 = 8x + 80
10x = 50 x = 5
Present age of son = x + 4 = 9 years
Present age of mother = 6x + 4 = 34 years
Required ratio = (34 + 2) : 9 = 4 : 1
Hence, the correct answer is 4 : 1.