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A person can cover a distance between A and B at a speed of 45 km/hr. On the return journey, he covers 180 km with 30 km/hr, and after that, he takes a different route on the return journey which increases his total distance by 15 km. If the speed of the car on the extended route is 60 km/hr. If it takes 90 min more while returning then find the distance between A and B.
310 km
315 km
320 km
325 km
330 km
Correct option : 2 - 315
While traveling from A to B speed = 45 km/hr On return journey 180 km with 30 km/hr. On new route the distance is increased by 15 km. Speed of the car on the extended route = 60 km/hr Return journey time = 90 min + forward journey time Calculation: Let the total distance from A to B = D km Time taken by person in the forward journey = D/45 ATQ, D/45 + 90/60 180/30+ (D+ 15 - 180)/60 D/45-D/606-1.5-2.75 (4D-3D)/180 = 1.75 ⇒ D = 315 km Hence, the correct answer is 315 km.
By: Parvesh Mehta ProfileResourcesReport error
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