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A bag contains 8 red and 5 blue balls. Two balls are drawn randomly. Find the probability that one ball is red and other is blue.
20/39
10/29
25/39
1/13
None of the above
To determine the probability that one ball is red and the other is blue, you can follow these steps:
- Calculate the total number of ways to draw two balls from the bag:
$$
\text{Total ways} = \binom{13}{2} = 78
This is because there are 13 balls in total (8 red + 5 blue).
- Calculate the number of favorable ways to draw one red and one blue ball:
- Ways to choose 1 red ball from 8 red balls:
\binom{8}{1} = 8
- Ways to choose 1 blue ball from 5 blue balls:
\binom{5}{1} = 5
- Total favorable ways:
8 \times 5 = 40
- Probability of drawing one red and one blue ball:
\frac{40}{78} = \frac{20}{39}
- Option 1, 20/39, matches the calculated probability.
Option 1: 20/39
- Correct calculation based on combinatorial mathematics.
Option 2: 10/29
- Not matching with probability calculation.
Option 3: 25/39
- Incorrect, not aligned with outcomes.
Option 4: 1/13
- Significantly off.
Option 5: None of the Above
- Not applicable as Option 1 is correct.
By: Parvesh Mehta ProfileResourcesReport error
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