Total number of NM min of all the three toys together is what percent more than total number of HR m...........

Quantitative Aptitude(IBPS PO) Case Studies

Directions : Given data is regarding three automatic toys on two types of movements: Neck movements (NM) and Hand rotation (HR). It starts recording from 9 AM onwards on 12 June. Each toy has different battery percentage and battery capacity.

Toy A: Battery Capacity = 1500 units, Battery Percent = 80%

At every 4th NM and 3rd HR together, 1 unit of battery is consumed. Toy A gets completely discharged at 11 AM.

Toy B: Battery Capacity = 2000 units, Battery percent = 75%

NM = 30/min, HR/min = 50% of NM/min of toy A. At every 3rd NM and 2nd HR together, 1 unit of battery is consumed. Toy C: Battery Capacity = 120% of battery capacity of toy B, Battery Percent = 60%

B, Battery Percent = 60% NM/min = NM/min of toy A + 5, HR = 30/min. at every 3rd NM and 2nd HR together. 1 unit of battery is consumed.

Total number of NM/min of all the three toys together is what percent more than total number of HR/min of all the three toys together?

This questions was previously asked in

IBPS PO Mains ( (Memory Based 2019))

View All IBPSPO Previous Year Papers

63.5%

52.25%

46.5%

48.25%

43.75%

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